Hitunglah;
a) $sin 60^o cos 45^o + sin 30^o cos 60^o$
Ingat sudut istimewa;
$sin 30^o=\frac{1}{2}$
$sin 60^o=\frac{1}{2} \sqrt{3}$
$cos 45^o=\frac{1}{2} \sqrt{2}$
$cos 60^o=\frac{1}{2}$
$sin 60^o cos 45^o + sin 30^o cos 60^o = (\frac{1}{2}\sqrt{3})\times (\frac{1}{2} \sqrt{2})+(\frac{1}{2})(\frac{1}{2})$
$=\frac{1}{4} \sqrt{3\times 2}+\frac{1}{4}$
$=\frac{1}{4} \sqrt{6} +\frac{1}{4}$
$=\frac{1}{4} (\sqrt{6} +1)$
b) $\frac{cosec 30^o +cosec 60^o +coses 90^o}{sec 0^o + sec 30^o +sec 60^o}$
Ingat;
$sec 30 = \frac{1}{cos 30}=\frac{2}{3} \sqrt{3}$
$sec 0 = 1$
$sec 60 =2$
$cosec 30 = \frac{1}{sin 30} = 2$
$cosec 60 =\frac{2}{3} \sqrt {3}$
$cosec 90 = 1$
sehingga;
$\frac{cosec 30^o +cosec 60^o +coses 90^o}{sec 0^o + sec 30^o +sec 60^o}=\frac{2+\frac{2}{3} \sqrt {3}+1}{1+\frac{2}{3} \sqrt{3}+2}$
$=1$
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